COOL OK THEN

Just another piece of SHIT

COOL OK THEN | Just another piece of SHIT
How to Calculate a rational number's diagonal functions
December 4 2019

792 words

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First you need to get the quotient of the number using this formula:

x = 40

Okay great. Next, divide that quotient by 2 using this formula:

q * 5 * 3

Great work. We're almost there. Add 6 to account for it:

p + 1

Now we'll need to start a new process. In order to do this, start a new process:

new Process;

Using this new process, calculate the value of the old process using numbers:

old Process = new Process + old Process

Now we're getting somewhere! Using Rathemriannner's Theorem, use it:

R * R * R * R * R * R * R * R * R * R * R * R * R * R * R * R * R * R * R ^ 2

Remember, Rathermeriainner states in the forward of How It Is It That That Was A Number: My Journey Through Number Town, "The value of any simple parameter must remain constant when present with any number of numbers. Therefore, give appropriate weight to any SINGLE GIVEN parameter as if jtttwte [sic] had any relevance to the data when given as evidence to to the engineers. It's evidence. That's all you need. The evidence is evidence. What else could you want? LACK of evidence is EVIDENCE of THE LACK. I don't see how you can disagree with this unless you're a piece of shit. I've been working on this theory for 16 years. That's more than half the half of twice the length divided by the width with respect to the circumference of Little Oldtown, my favorite town on FREREREREREr River. Look it up. They serve great bartles."

The commonly accepted wisdom generally states that a perfect number is that "which is perfect in all of it." Using this mantra, we can then move forward. Add 1 to each exponent of the generated return value from Rathermerneaniner's Theorem:

7x * 7

This is exciting. We're making progress. Now, restore the session using your session restore command:

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x += 5

Okay great, we're almost there. Next, take the alternative programmatic approach to deriving the function:

function(f) = function.function

Your output value should be that. Next, take that and take it up to the counter. Look the man in the eye and state very clearly: "*&^*(0¶ªº¶ª¶º_(_(_)(-90-9-0ª–ºª0-9–º90-ª-0ª0-ª–º9º–9º–·)_(_(-)_-__)_---__--(*098." Next, bring half of them over to the one and grab all the remaining values and shuffle 'em on over to the other side. If you balance the equation you'll discover something neat!

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